What is area y=5cos(2x),y=5sin(4x),x=0,x= pi/4 ?

The answer to area y=5cos(2x),y=5sin(4x),x=0,x= pi/4 is 5/4

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area y=5cos(2x),y=5sin(4x),x=0,x= pi/4

area

y = 5 cos (2 x), y = 5 sin (4 x), x = 0, x = \frac{π}{4}

\frac{5}{4}

Decimal Notation

1.25

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{4}} ∣ 5 cos (2 x) - 5 sin (4 x) ∣ d x

Solve

\int_{0}^{\frac{π}{4}} ∣ 5 cos (2 x) - 5 sin (4 x) ∣ d x : \frac{5}{4}

The area is:

= \frac{5}{4}

cos (\frac{t}{2})

\frac{22.96}{( s + 10.7 )}

x \to 2 lim (\frac{sin ( x )}{x})

\frac{d}{d x} (ln (\frac{1}{4} e^{x} + \frac{3}{4} e^{- x}))

\frac{d}{d x} (ln ∣ x - 1 ∣)

What is area y=5cos(2x),y=5sin(4x),x=0,x= pi/4 ?
The answer to area y=5cos(2x),y=5sin(4x),x=0,x= pi/4 is 5/4