What is inverse oflaplace (22.96)/((s+10.7)) ?

The answer to inverse oflaplace (22.96)/((s+10.7)) is 22.96e^{-10.7t}

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inverse oflaplace (22.96)/((s+10.7))

inverse laplace

\frac{22.96}{( s + 10.7 )}

22.96 e^{- 10.7 t}

Solution steps

L^{- 1} {\frac{22.96}{( s + 10.7 )}}

= L^{- 1} {22.96 \cdot \frac{1}{s + 10.7}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 22.96 L^{- 1} {\frac{1}{s + 10.7}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 10.7}} = e^{- 10.7 t}

= 22.96 e^{- 10.7 t}

x \to 2 lim (\frac{sin ( x )}{x})

\frac{d}{d x} (ln (\frac{1}{4} e^{x} + \frac{3}{4} e^{- x}))

\frac{d}{d x} (ln ∣ x - 1 ∣)

f^{^{'}} (x) = cos (x), f (0) = - 5

\frac{d}{d x} (sin^{2} (- 3 x + 6))

What is inverse oflaplace (22.96)/((s+10.7)) ?
The answer to inverse oflaplace (22.96)/((s+10.7)) is 22.96e^{-10.7t}