What is the derivative of sin^2(-3x+6) ?

The derivative of sin^2(-3x+6) is -6sin(-3x+6)cos(-3x+6)

What is the first derivative of sin^2(-3x+6) ?

The first derivative of sin^2(-3x+6) is -6sin(-3x+6)cos(-3x+6)

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\frac{d}{d x} (sin^{2} (- 3 x + 6))

- 6 sin (- 3 x + 6) cos (- 3 x + 6)

Solution steps

\frac{d}{d x} (sin^{2} (- 3 x + 6))

Apply the chain rule:

2 sin (- 3 x + 6) \frac{d}{d x} (sin (- 3 x + 6))

= 2 sin (- 3 x + 6) \frac{d}{d x} (sin (- 3 x + 6))

\frac{d}{d x} (sin (- 3 x + 6)) = - 3 cos (- 3 x + 6)

= 2 sin (- 3 x + 6) (- 3 cos (- 3 x + 6))

Simplify

= - 6 sin (- 3 x + 6) cos (- 3 x + 6)

(- 10, 3), (- 8, - 8)

n = 0 \sum \infty (\frac{1}{5})^{n + 1}

\int (e^{x} + 2 x)^{2} d x

\int \frac{x ^{3}}{1 - x ^{4}} d x

f (x) = 5 - 3 x

What is the derivative of sin^2(-3x+6) ?
The derivative of sin^2(-3x+6) is -6sin(-3x+6)cos(-3x+6)
What is the first derivative of sin^2(-3x+6) ?
The first derivative of sin^2(-3x+6) is -6sin(-3x+6)cos(-3x+6)