What is the derivative of (2-x)/8 ?

The derivative of (2-x)/8 is -1/8

What is the first derivative of (2-x)/8 ?

The first derivative of (2-x)/8 is -1/8

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derivative of

\frac{2 - x}{8}

- \frac{1}{8}

Solution steps

\frac{d}{d x} (\frac{2 - x}{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (2 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{8} (\frac{d}{d x} (2) - \frac{d x}{d x})

\frac{d}{d x} (2) = 0

\frac{d x}{d x} = 1

= \frac{1}{8} (0 - 1)

Simplify

= - \frac{1}{8}

\int x \cdot e^{3 x} d x

\frac{d ^{2} y}{d x ^{2}} + 9 y = 10 cos (2 x)

\frac{x ^{3} + 8}{x}

x \to 0 + lim (lo g_{4} (2))

What is the derivative of (2-x)/8 ?
The derivative of (2-x)/8 is -1/8
What is the first derivative of (2-x)/8 ?
The first derivative of (2-x)/8 is -1/8