What is the integral of 1/(x\sqrt[8]{x)} ?

The integral of 1/(x\sqrt[8]{x)} is -8/(\sqrt[8]{x)}+C

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integral of 1/(x\sqrt[8]{x)}

Solution steps

Simplify

= \int \frac{1}{x ^{\frac{9}{8}}} d x

Apply the Power Rule

Add a constant to the solution

7 t \cdot \frac{d y}{d t} - 4 y = t

\frac{d}{d x} (1 - sin (3 x))

\frac{e ^{- 5 s}}{s ^{2}}

x \to 3 + lim (\frac{( x ^{2} )}{x - 3})

\int_{0}^{1} 2 π (2 - y) (5 y^{2}) d y

What is the integral of 1/(x\sqrt[8]{x)} ?
The integral of 1/(x\sqrt[8]{x)} is -8/(\sqrt[8]{x)}+C