What is laplacetransform f(t)=cos(t) ?

The answer to laplacetransform f(t)=cos(t) is s/(s^2+1)

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laplacetransform f(t)=cos(t)

laplace transform

f (t) = cos (t)

\frac{s}{s ^{2} + 1}

Solution steps

L {cos (t)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (t)} = \frac{s}{s ^{2} + 1 ^{2}}

= \frac{s}{s ^{2} + 1 ^{2}}

= \frac{s}{s ^{2} + 1}

n = 0 \sum \infty \frac{1 0 ^{n}}{n !}

y^{^{'}} = - 5 y^{2}

f (x) = arctan (7 x)

f (x) = csc (x) cot (x)

(\frac{x}{2 y ^{4}}) d x + (\frac{3 y ^{2} - x ^{2}}{y ^{5}}) d y = 0

What is laplacetransform f(t)=cos(t) ?
The answer to laplacetransform f(t)=cos(t) is s/(s^2+1)