What is the derivative of ((x^2+1/(2x-1))^2) ?

The derivative of ((x^2+1/(2x-1))^2) is (2(x^2+1)(2x^2-2x-2))/((2x-1)^3)

What is the first derivative of ((x^2+1/(2x-1))^2) ?

The first derivative of ((x^2+1/(2x-1))^2) is (2(x^2+1)(2x^2-2x-2))/((2x-1)^3)

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\frac{d}{d x} ((\frac{x ^{2} + 1}{2 x - 1})^{2})

\frac{2 ( x ^{2} + 1 ) ( 2 x ^{2} - 2 x - 2 )}{( 2 x - 1 ) ^{3}}

Solution steps

\frac{d}{d x} ((\frac{x ^{2} + 1}{2 x - 1})^{2})

Apply the chain rule:

2 \cdot \frac{x ^{2} + 1}{2 x - 1} \frac{d}{d x} (\frac{x ^{2} + 1}{2 x - 1})

= 2 \cdot \frac{x ^{2} + 1}{2 x - 1} \frac{d}{d x} (\frac{x ^{2} + 1}{2 x - 1})

\frac{d}{d x} (\frac{x ^{2} + 1}{2 x - 1}) = \frac{2 x ^{2} - 2 x - 2}{( 2 x - 1 ) ^{2}}

= 2 \cdot \frac{x ^{2} + 1}{2 x - 1} \cdot \frac{2 x ^{2} - 2 x - 2}{( 2 x - 1 ) ^{2}}

Simplify

2 \cdot \frac{x ^{2} + 1}{2 x - 1} \cdot \frac{2 x ^{2} - 2 x - 2}{( 2 x - 1 ) ^{2}} : \frac{2 ( x ^{2} + 1 ) ( 2 x ^{2} - 2 x - 2 )}{( 2 x - 1 ) ^{3}}

= \frac{2 ( x ^{2} + 1 ) ( 2 x ^{2} - 2 x - 2 )}{( 2 x - 1 ) ^{3}}

\frac{d}{d x} (\frac{9 ( x - 3 )}{( x - 1 ) ^{3}})

x \to 5 - lim (\frac{1}{x ^{2} - 25})

\frac{\partial}{\partial t} (\frac{3 s + t}{4 s - t})

2 y cos (x) d x + 3 sin (x) d y = 0

e^{x} y \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

What is the derivative of ((x^2+1/(2x-1))^2) ?
The derivative of ((x^2+1/(2x-1))^2) is (2(x^2+1)(2x^2-2x-2))/((2x-1)^3)
What is the first derivative of ((x^2+1/(2x-1))^2) ?
The first derivative of ((x^2+1/(2x-1))^2) is (2(x^2+1)(2x^2-2x-2))/((2x-1)^3)