What is the sum from n=1 to infinity of ((n+1)/n)^n ?

The sum from n=1 to infinity of ((n+1)/n)^n is diverges

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sum from n=1 to infinity of ((n+1)/n)^n

n = 1 \sum \infty (\frac{n + 1}{n})^{n}

diverges

Solution steps

n = 1 \sum \infty (\frac{n + 1}{n})^{n}

Apply Series Divergence Test:

diverges

= diverges

y^{^{''}} - 2 y^{^{'}} + y = x e^{- x}

\frac{\partial}{\partial z} (x^{a} y^{b} z^{c})

\frac{d y}{d x} = \frac{( y - 1 )}{x + 3}

y^{^{'}} + \frac{y}{x} = 7 x^{3} y^{2}

3^{x}

What is the sum from n=1 to infinity of ((n+1)/n)^n ?
The sum from n=1 to infinity of ((n+1)/n)^n is diverges