What is (\partial)/(\partial y)(sin(2x+5y)) ?

The answer to (\partial)/(\partial y)(sin(2x+5y)) is cos(2x+5y)*5

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(\partial)/(\partial y)(sin(2x+5y))

\frac{\partial}{\partial y} (sin (2 x + 5 y))

cos (2 x + 5 y) \cdot 5

Solution steps

\frac{\partial}{\partial y} (sin (2 x + 5 y))

Treat

x

as a constant

Apply the chain rule:

cos (2 x + 5 y) \frac{\partial}{\partial y} (2 x + 5 y)

= cos (2 x + 5 y) \frac{\partial}{\partial y} (2 x + 5 y)

\frac{\partial}{\partial y} (2 x + 5 y) = 5

= cos (2 x + 5 y) \cdot 5

\int_{1}^{4} 2 t ln (t) d t

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\frac{\partial}{\partial x} (20)

\frac{\partial}{\partial y} (\frac{1}{4} x^{2} + y^{2} - 1)

g (x) = x^{2} + sin (x)

What is (\partial)/(\partial y)(sin(2x+5y)) ?
The answer to (\partial)/(\partial y)(sin(2x+5y)) is cos(2x+5y)*5