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Popular >

integral of 1/(y+1)

Solution

\int \frac{1}{y + 1} d y

Solution

ln ∣ y + 1 ∣ + C

Solution steps

\int \frac{1}{y + 1} d y

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = y + 1

= ln ∣ y + 1 ∣

Add a constant to the solution

= ln ∣ y + 1 ∣ + C

Popular Examples

integral of sin^3(4x)cos^9(4x)

\int sin^{3} (4 x) cos^{9} (4 x) d x

integral of (ln(x^{26}))/x

\int \frac{ln ( x ^{26} )}{x} d x

(\partial)/(\partial x)(240x^2-140y^2)

\frac{\partial}{\partial x} (240 x^{2} - 140 y^{2})

laplacetransform tcos(5t)laplace transform

t cos (5 t)

limit as x approaches-9 of-9

x \to - 9 lim (- 9)

Frequently Asked Questions (FAQ)

What is the integral of 1/(y+1) ?
The integral of 1/(y+1) is ln|y+1|+C