What is area y= 1/(x^2)+x,x=2,x=4 ?

The answer to area y= 1/(x^2)+x,x=2,x=4 is 25/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y= 1/(x^2)+x,x=2,x=4

area

y = \frac{1}{x ^{2}} + x, x = 2, x = 4

\frac{25}{4}

Decimal Notation

6.25

Solution steps

Apply the area formula:

\int_{2}^{4} \frac{1}{x ^{2}} + x d x

Solve

\int_{2}^{4} \frac{1}{x ^{2}} + x d x : \frac{25}{4}

The area is:

= \frac{25}{4}

x \to 0 lim (x^{6} sin (x))

f (x) = e^{x} - 2 x

\frac{d}{d x} ((3 x - 1) (x + 2))

x \to 0 + lim (2 - x)

y^{^{'}} = y - 8

What is area y= 1/(x^2)+x,x=2,x=4 ?
The answer to area y= 1/(x^2)+x,x=2,x=4 is 25/4