What is the integral of (3x^2-7x+4) ?

The integral of (3x^2-7x+4) is x^3-(7x^2)/2+4x+C

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integral of (3x^2-7x+4)

\int (3 x^{2} - 7 x + 4) d x

x^{3} - \frac{7 x ^{2}}{2} + 4 x + C

Solution steps

\int 3 x^{2} - 7 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 7 x d x + \int 4 d x

\int 3 x^{2} d x = x^{3}

\int 7 x d x = \frac{7 x ^{2}}{2}

\int 4 d x = 4 x

= x^{3} - \frac{7 x ^{2}}{2} + 4 x

Add a constant to the solution

= x^{3} - \frac{7 x ^{2}}{2} + 4 x + C

\int \frac{3 x ^{3} 9 x ^{2} - 15}{x ^{2} 4 x ^{4}} d x

\frac{d}{d x} (arcsin (3 x + y))

\frac{d}{d x} (ln (5 x + 3))

\int 4 e^{- x} (e^{- 3 x} + 1) d x

\frac{d}{d x} (\frac{9 x}{e ^{x}})

What is the integral of (3x^2-7x+4) ?
The integral of (3x^2-7x+4) is x^3-(7x^2)/2+4x+C