What is the derivative of (9x/(e^x)) ?

The derivative of (9x/(e^x)) is (9(1-x))/(e^x)

What is the first derivative of (9x/(e^x)) ?

The first derivative of (9x/(e^x)) is (9(1-x))/(e^x)

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\frac{d}{d x} (\frac{9 x}{e ^{x}})

\frac{9 ( 1 - x )}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{9 x}{e ^{x}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 9 \cdot \frac{\frac{d x}{d x} e ^{x} - \frac{d}{d x} ( e ^{x} ) x}{( e ^{x} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 9 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}}

Simplify

9 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}} : \frac{9 ( 1 - x )}{e ^{x}}

= \frac{9 ( 1 - x )}{e ^{x}}

f (x) = arccos (3 x)

\frac{d}{d x} (arctan (x - 1 + x^{2}))

\frac{d y}{d x} = x^{2} (1 - y)

\frac{\partial}{\partial y} (2 x^{2} y - 5 y^{2})

What is the derivative of (9x/(e^x)) ?
The derivative of (9x/(e^x)) is (9(1-x))/(e^x)
What is the first derivative of (9x/(e^x)) ?
The first derivative of (9x/(e^x)) is (9(1-x))/(e^x)