What is (\partial)/(\partial x)(4x^2-2y) ?

The answer to (\partial)/(\partial x)(4x^2-2y) is 8x

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(\partial)/(\partial x)(4x^2-2y)

\frac{\partial}{\partial x} (4 x^{2} - 2 y)

8 x

Solution steps

\frac{\partial}{\partial x} (4 x^{2} - 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{2}) - \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (4 x^{2}) = 8 x

\frac{\partial}{\partial x} (2 y) = 0

= 8 x - 0

Simplify

= 8 x

\frac{d}{d x} (ln ((sin (x) cos (x))^{2}))

\int x^{2} in (x) d x

\frac{d}{d x} (e^{x} y)

f (x) = sin (sin (x)), (π, 0)

\int \frac{9 x ( 6 x ^{2} + 5 ) ^{\frac{1}{2}}}{2} d x

What is (\partial)/(\partial x)(4x^2-2y) ?
The answer to (\partial)/(\partial x)(4x^2-2y) is 8x