What is area y=9-0.25x^2,y=1,2<x<5 ?

The answer to area y=9-0.25x^2,y=1,2<x<5 is 14.25

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area y=9-0.25x^2,y=1,2<x<5

area

y = 9 - 0.25 x^{2}, y = 1, 2 < x < 5

14.25

Solution steps

Apply the area formula:

\int_{2}^{5} - 0.25 x^{2} + 8 d x

Solve

\int_{2}^{5} - 0.25 x^{2} + 8 d x : 14.25

The area is:

= 14.25

\frac{\partial}{\partial x} (\frac{x}{x ^{2} + 9 y ^{2}})

\int (x + 1 + x^{2})^{6} d x

\int sec^{4} (5 x) tan (5 x) d x

x \to 2 lim (sin (\frac{p i x}{2}))

\frac{d}{d x} (5 x^{2} e^{- x})

What is area y=9-0.25x^2,y=1,2<x<5 ?
The answer to area y=9-0.25x^2,y=1,2<x<5 is 14.25