What is the integral from 0 to pi/2 of 2-sin(x) ?

The integral from 0 to pi/2 of 2-sin(x) is pi-1

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integral from 0 to pi/2 of 2-sin(x)

\int_{0}^{\frac{π}{2}} 2 - sin (x) d x

π - 1

Decimal Notation

2.14159 \dots

Solution steps

\int_{0}^{\frac{π}{2}} 2 - sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{2}} 2 d x - \int_{0}^{\frac{π}{2}} sin (x) d x

\int_{0}^{\frac{π}{2}} 2 d x = π

\int_{0}^{\frac{π}{2}} sin (x) d x = 1

= π - 1

\frac{d ^{2}}{d x ^{2}} (x (1 + x^{2})^{10})

3 x^{- 5}

\frac{\partial}{\partial v} (u sin (v))

x \to π lim (sec (x))

\int \frac{( 2 x + 4 )}{x ^{2} + 5 x - 6} d x

What is the integral from 0 to pi/2 of 2-sin(x) ?
The integral from 0 to pi/2 of 2-sin(x) is pi-1