What is the derivative of-3cos(3x) ?

The derivative of-3cos(3x) is 9sin(3x)

What is the first derivative of-3cos(3x) ?

The first derivative of-3cos(3x) is 9sin(3x)

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derivative of

- 3 cos (3 x)

9 sin (3 x)

Solution steps

\frac{d}{d x} (- 3 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 3 (- sin (3 x) \cdot 3)

Simplify

= 9 sin (3 x)

f (x) = \frac{x ^{2}}{x ^{3} + 1}

\int_{2}^{7} \frac{1}{x - 2} d x

f (x) = e^{4 x s i n (2 x)}

\frac{\partial}{\partial x} (\frac{e ^{x}}{u ( x ) + x ^{2}})

y^{^{''}} - \frac{9}{x} y^{^{'}} + \frac{34}{x ^{2}} y = 0

What is the derivative of-3cos(3x) ?
The derivative of-3cos(3x) is 9sin(3x)
What is the first derivative of-3cos(3x) ?
The first derivative of-3cos(3x) is 9sin(3x)