What is the sum from n=1 to infinity of 2/(3n+10) ?

The sum from n=1 to infinity of 2/(3n+10) is diverges

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sum from n=1 to infinity of 2/(3n+10)

n = 1 \sum \infty \frac{2}{3 n + 10}

diverges

Solution steps

n = 1 \sum \infty \frac{2}{3 n + 10}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{1}{3 n + 10}

Apply Series Limit Comparison Test:

diverges

= 2 diverges

= diverges

\int_{1}^{2} 4 x 4 x^{2} + 4 d x

\int (3 x^{4} - 5 x^{2} + 6 x) d x

x \to 0 lim (\frac{∣ x + 1 ∣ - ∣ x - 1 ∣}{x})

n = 1 \sum \infty 8

\frac{\partial}{\partial v} (u^{2} + v^{2})

What is the sum from n=1 to infinity of 2/(3n+10) ?
The sum from n=1 to infinity of 2/(3n+10) is diverges