What is the d/(ds)(ln(s^2+1)) ?

The d/(ds)(ln(s^2+1)) is (2s)/(s^2+1)

What is the first d/(ds)(ln(s^2+1)) ?

The first d/(ds)(ln(s^2+1)) is (2s)/(s^2+1)

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\frac{d}{d s} (ln (s^{2} + 1))

\frac{2 s}{s ^{2} + 1}

Solution steps

\frac{d}{d s} (ln (s^{2} + 1))

Apply the chain rule:

\frac{1}{s ^{2} + 1} \frac{d}{d s} (s^{2} + 1)

= \frac{1}{s ^{2} + 1} \frac{d}{d s} (s^{2} + 1)

\frac{d}{d s} (s^{2} + 1) = 2 s

= \frac{1}{s ^{2} + 1} \cdot 2 s

Simplify

\frac{1}{s ^{2} + 1} \cdot 2 s : \frac{2 s}{s ^{2} + 1}

= \frac{2 s}{s ^{2} + 1}

\int (4 x^{3} + 7) d x

\frac{\partial}{\partial x} (z sin (x) + y^{2})

\int \frac{x}{( x + 2 ) ^{\frac{2}{3}}} d x

x \to 0 lim (cos (\frac{π}{2}))

y = 8 e^{x} cos (x)

What is the d/(ds)(ln(s^2+1)) ?
The d/(ds)(ln(s^2+1)) is (2s)/(s^2+1)
What is the first d/(ds)(ln(s^2+1)) ?
The first d/(ds)(ln(s^2+1)) is (2s)/(s^2+1)