What is the derivative of-4x^4+8x^3 ?

The derivative of-4x^4+8x^3 is -16x^3+24x^2

What is the first derivative of-4x^4+8x^3 ?

The first derivative of-4x^4+8x^3 is -16x^3+24x^2

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\frac{d}{d x} (- 4 x^{4} + 8 x^{3})

- 16 x^{3} + 24 x^{2}

Solution steps

\frac{d}{d x} (- 4 x^{4} + 8 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 x^{4}) + \frac{d}{d x} (8 x^{3})

\frac{d}{d x} (4 x^{4}) = 16 x^{3}

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

= - 16 x^{3} + 24 x^{2}

\frac{( 3 s + 1 )}{s ( s + 2 )}

y^{^{'}} - \frac{6}{x} y = \frac{( y ^{5} )}{x ^{18}}, y (1) = 1

g (x) = 3 (5 - 7 x)^{5}

\frac{d x}{d y} = 7 sin (x) + 3 cos (x)

\frac{d}{d x} (sin (\frac{π}{4}))

What is the derivative of-4x^4+8x^3 ?
The derivative of-4x^4+8x^3 is -16x^3+24x^2
What is the first derivative of-4x^4+8x^3 ?
The first derivative of-4x^4+8x^3 is -16x^3+24x^2