What is the solution for y^'-6/x y=((y^5))/(x^{18)},y(1)=1 ?

The solution for y^'-6/x y=((y^5))/(x^{18)},y(1)=1 is y=(\sqrt[4]{7}x^6)/(\sqrt[4]{-4x^7+11)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-6/x y=((y^5))/(x^{18)},y(1)=1

y^{^{'}} - \frac{6}{x} y = \frac{( y ^{5} )}{x ^{18}}, y (1) = 1

Solution steps

y^{'} (x) - \frac{6}{x} y = \frac{( y ^{5} )}{x ^{18}}

Solve Bernoulli ODE:

g (x) = 3 (5 - 7 x)^{5}

\frac{d x}{d y} = 7 sin (x) + 3 cos (x)

\frac{d}{d x} (sin (\frac{π}{4}))

\int \frac{7 e ^{2 t}}{1 + e ^{4 t}} d t

\frac{d}{d x} (x^{3} - 2 x + 4)

What is the solution for y^'-6/x y=((y^5))/(x^{18)},y(1)=1 ?
The solution for y^'-6/x y=((y^5))/(x^{18)},y(1)=1 is y=(\sqrt[4]{7}x^6)/(\sqrt[4]{-4x^7+11)}