What is the derivative of x^3-2x+4 ?

The derivative of x^3-2x+4 is 3x^2-2

What is the first derivative of x^3-2x+4 ?

The first derivative of x^3-2x+4 is 3x^2-2

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\frac{d}{d x} (x^{3} - 2 x + 4)

3 x^{2} - 2

Solution steps

\frac{d}{d x} (x^{3} - 2 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4) = 0

= 3 x^{2} - 2 + 0

Simplify

= 3 x^{2} - 2

3 x^{\frac{4}{3}}

x \to 1 lim (\frac{x ^{2} - 1}{x - 3})

cos (a x + b)

\frac{d}{d x} (\frac{( x ^{2} )}{7 + 6 x})

\int 5 (1 - x)^{4} d x

What is the derivative of x^3-2x+4 ?
The derivative of x^3-2x+4 is 3x^2-2
What is the first derivative of x^3-2x+4 ?
The first derivative of x^3-2x+4 is 3x^2-2