What is (\partial)/(\partial y)(4x^2+3cos(y)) ?

The answer to (\partial)/(\partial y)(4x^2+3cos(y)) is -3sin(y)

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(\partial)/(\partial y)(4x^2+3cos(y))

\frac{\partial}{\partial y} (4 x^{2} + 3 cos (y))

- 3 sin (y)

Solution steps

\frac{\partial}{\partial y} (4 x^{2} + 3 cos (y))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x^{2}) + \frac{\partial}{\partial y} (3 cos (y))

\frac{\partial}{\partial y} (4 x^{2}) = 0

\frac{\partial}{\partial y} (3 cos (y)) = - 3 sin (y)

= 0 - 3 sin (y)

Simplify

= - 3 sin (y)

\frac{d}{d x} (x^{2} + \frac{4}{x})

\frac{\partial}{\partial x} (ln (3 x + 3 cy))

cos (5 π x)

\frac{5 - x ^{2}}{5 + x ^{2}}

\int 7 x^{2} ln (x) d x

What is (\partial)/(\partial y)(4x^2+3cos(y)) ?
The answer to (\partial)/(\partial y)(4x^2+3cos(y)) is -3sin(y)