What is the slope ofintercept (-3,2),(-1,-1) ?

The slope ofintercept (-3,2),(-1,-1) is y=-3/2 x-5/2

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slope ofintercept (-3,2),(-1,-1)

slope intercept

(- 3, 2), (- 1, - 1)

y = - \frac{3}{2} x - \frac{5}{2}

Solution steps

Compute the slope

(- 3, 2), (- 1, - 1) : m = - \frac{3}{2}

Compute the

y

intercept:

b = - \frac{5}{2}

Construct the line equation

y = mx + b

where

m = - \frac{3}{2}

and

b = - \frac{5}{2}

y = - \frac{3}{2} x - \frac{5}{2}

x \to 1 lim (3 x^{2} - 6 x + 1)

x x^{2} + 9

\frac{d}{d x} (x^{4} - 32 x^{2})

y^{^{''}} + 2 y^{^{'}} + 10 y = 0, y (0) = 3, y^{^{'}} (0) = - 1

x \to 2 lim (4 x^{2} - 8 x)

What is the slope ofintercept (-3,2),(-1,-1) ?
The slope ofintercept (-3,2),(-1,-1) is y=-3/2 x-5/2