What is the derivative of x^3-4x^2 ?

The derivative of x^3-4x^2 is 3x^2-8x

What is the first derivative of x^3-4x^2 ?

The first derivative of x^3-4x^2 is 3x^2-8x

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derivative of

x^{3} - 4 x^{2}

3 x^{2} - 8 x

Solution steps

\frac{d}{d x} (x^{3} - 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

= 3 x^{2} - 8 x

y^{^{'}} = - a y^{2} + b

\frac{d}{d x} (tan (1 + e^{2 x}))

- 2 lo g_{e} (x) + x^{2} - 4 + e^{x} + x^{e}

\int 2 csc^{4} (x) cot^{6} (x) d x

x \to - 2 lim (7 - 2 x)

What is the derivative of x^3-4x^2 ?
The derivative of x^3-4x^2 is 3x^2-8x
What is the first derivative of x^3-4x^2 ?
The first derivative of x^3-4x^2 is 3x^2-8x