What is the derivative of sqrt(2)x ?

The derivative of sqrt(2)x is square root of 2

What is the first derivative of sqrt(2)x ?

The first derivative of sqrt(2)x is square root of 2

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\frac{d}{d x} (2 x)

2

Solution steps

\frac{d}{d x} (2 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 \cdot 1

Simplify

= 2

f (x) = x^{2} - 2 x - 6, at x = - 2

x \to 8 lim (\frac{4}{x - 8})

\int_{0}^{6} 15 4 x + 1 d x

\frac{d}{d x} (\frac{- 2 ( - 3 x ^{2} + 1 )}{( 1 + x ^{2} ) ^{3}})

\frac{d}{d x} (\frac{2 arcsin ( x )}{1 - x ^{2}})

What is the derivative of sqrt(2)x ?
The derivative of sqrt(2)x is square root of 2
What is the first derivative of sqrt(2)x ?
The first derivative of sqrt(2)x is square root of 2