What is the solution for (dy)/(dx)=e^{3x+4y} ?

The solution for (dy)/(dx)=e^{3x+4y} is y=-(ln(-4/3 e^{3x}-c_{1}))/4

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(dy)/(dx)=e^{3x+4y}

\frac{d y}{d x} = e^{3 x + 4 y}

y = - \frac{ln ( - \frac{4}{3} e ^{3 x} - c _{1} )}{4}

Solution steps

\frac{d y}{d x} = e^{3 x + 4 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{4}{3} e ^{3 x} - c _{1} )}{4}

y = - \frac{ln ( - \frac{4}{3} e ^{3 x} - c _{1} )}{4}

x \to 0 lim (7 x + 3)

y 3 - x y 2 + x 3 = 5

n = 1 \sum \infty (\frac{n}{n + 1})^{n}

\int 6 sin^{2} (x) cos^{3} (x) d x

\int \frac{1}{- t ^{2} + 4 t + 5} d t

What is the solution for (dy)/(dx)=e^{3x+4y} ?
The solution for (dy)/(dx)=e^{3x+4y} is y=-(ln(-4/3 e^{3x}-c_{1}))/4