What is the derivative of 2/(3t^2) ?

The derivative of 2/(3t^2) is -4/(3t^3)

What is the first derivative of 2/(3t^2) ?

The first derivative of 2/(3t^2) is -4/(3t^3)

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derivative of

\frac{2}{3 t ^{2}}

- \frac{4}{3 t ^{3}}

Solution steps

\frac{d}{d t} (\frac{2}{3 t ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{3} \frac{d}{d t} (\frac{1}{t ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{2}{3} \frac{d}{d t} (t^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3} (- 2 t^{- 2 - 1})

Simplify

\frac{2}{3} (- 2 t^{- 2 - 1}) : - \frac{4}{3 t ^{3}}

= - \frac{4}{3 t ^{3}}

\int \frac{1}{2} x^{4} d x

\frac{440 t}{( t ^{2} + 6 ) ^{3}}

f (x) = sin^{5} (3 x)

\frac{7 x}{x + 4} (3.3)

\frac{d}{d x} ((x^{3} + x)^{6})

What is the derivative of 2/(3t^2) ?
The derivative of 2/(3t^2) is -4/(3t^3)
What is the first derivative of 2/(3t^2) ?
The first derivative of 2/(3t^2) is -4/(3t^3)