What is the tangent of (7x)/(x+4)(3.3) ?

The tangent of (7x)/(x+4)(3.3) is y=(92.4)/((a_{0)+4)^2}x+(23.1a_{0}^2)/((a_{0)+4)^2}

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tangent of (7x)/(x+4)(3.3)

tangent of

\frac{7 x}{x + 4} (3.3)

y = \frac{92.4}{( a _{0} + 4 ) ^{2}} x + \frac{23.1 a _{0}^{2}}{( a _{0} + 4 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{23.1 a _{0}}{a _{0} + 4})

Find the slope of

y = \frac{7 x}{x + 4} 3.3 : \frac{d y}{d x} = \frac{92.4}{( x + 4 ) ^{2}}

Compute the slope of

y = \frac{7 x}{x + 4} 3.3

x = a_{0} : m = \frac{92.4}{( a _{0} + 4 ) ^{2}}

Find the line with slope m=

\frac{92.4}{( a _{0} + 4 ) ^{2}}

and passing through

(a_{0}, \frac{23.1 a _{0}}{a _{0} + 4}) : y = \frac{92.4}{( a _{0} + 4 ) ^{2}} x + \frac{23.1 a _{0}^{2}}{( a _{0} + 4 ) ^{2}}

y = \frac{92.4}{( a _{0} + 4 ) ^{2}} x + \frac{23.1 a _{0}^{2}}{( a _{0} + 4 ) ^{2}}

\frac{d}{d x} ((x^{3} + x)^{6})

ln (x + x^{2} - 10)

sin (9 x)

\frac{d}{d x} (x + 1 - x)

\frac{d}{d θ} (3 tan (θ))

What is the tangent of (7x)/(x+4)(3.3) ?
The tangent of (7x)/(x+4)(3.3) is y=(92.4)/((a_{0)+4)^2}x+(23.1a_{0}^2)/((a_{0)+4)^2}