What is maclaurin sin(9x) ?

The answer to maclaurin sin(9x) is 9x-243/2 x^3+19683/40 x^5-531441/560 x^7+4782969/4480 x^9+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

maclaurin sin(9x)

maclaurin

sin (9 x)

9 x - \frac{243}{2} x^{3} + \frac{19683}{40} x^{5} - \frac{531441}{560} x^{7} + \frac{4782969}{4480} x^{9} + \dots

Solution steps

Apply the Maclaurin Formula

= 0 + \frac{\frac{d}{d x} ( sin ( 9 x ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( sin ( 9 x ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( sin ( 9 x ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{9}{1 !} x + \frac{0}{2 !} x^{2} + \frac{- 729}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{59049}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{- 4782969}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{387420489}{9 !} x^{9} + \dots

Refine

= 9 x - \frac{243}{2} x^{3} + \frac{19683}{40} x^{5} - \frac{531441}{560} x^{7} + \frac{4782969}{4480} x^{9} + \dots

\frac{d}{d x} (x + 1 - x)

\frac{d}{d θ} (3 tan (θ))

n = 1 \sum \infty a^{n - 1} \cdot n

\int sin (x + 5) d x

\int 3 x^{2} - 2 x + 5 d x

What is maclaurin sin(9x) ?
The answer to maclaurin sin(9x) is 9x-243/2 x^3+19683/40 x^5-531441/560 x^7+4782969/4480 x^9+\ldots