What is area y=e^x,y=e^{5x},x=1 ?

The answer to area y=e^x,y=e^{5x},x=1 is -e+1+(e^5-1)/5

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area y=e^x,y=e^{5x},x=1

area

y = e^{x}, y = e^{5 x}, x = 1

- e + 1 + \frac{e ^{5} - 1}{5}

Decimal Notation

27.76434 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} e^{x} - e^{5 x} d x

Solve

\int_{0}^{1} e^{x} - e^{5 x} d x : - e + 1 + \frac{e ^{5} - 1}{5}

The area is:

= - e + 1 + \frac{e ^{5} - 1}{5}

\frac{d y}{d t} = - 2 t cos (t^{2}) y + 6 t^{2} e^{- s i n (t^{2})}

\int π \cdot x d x

x \to 1 lim (x^{\frac{5}{x ^{2} - 1}})

f (x) = x arcsin (x)

\frac{d}{d x} (\frac{6 x + 5}{7 - 3 x ^{2}})

What is area y=e^x,y=e^{5x},x=1 ?
The answer to area y=e^x,y=e^{5x},x=1 is -e+1+(e^5-1)/5