What is the integral of 1/(\sqrt[3]{x^2)} ?

The integral of 1/(\sqrt[3]{x^2)} is 3\sqrt[3]{x}+C

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integral of 1/(\sqrt[3]{x^2)}

Solution steps

assuming

x \geq 0

= \int \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: 3 x^{\frac{1}{3}}

= 3 x^{\frac{1}{3}}

Apply radical rule:

Add a constant to the solution

\int cot (θ) d θ

\int (x (3 x - x) + (e^{e x} + 8)) d x

\frac{\partial}{\partial y} (x^{2} y^{2} - x y + 2)

\int_{1}^{4} 5 e^{x} d x

y^{^{''}} + 81 y = 5 tan (9 x)

What is the integral of 1/(\sqrt[3]{x^2)} ?
The integral of 1/(\sqrt[3]{x^2)} is 3\sqrt[3]{x}+C