What is the limit as x approaches 0+of (x+1)^{inx} ?

The limit as x approaches 0+of (x+1)^{inx} is 1

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limit as x approaches 0+of (x+1)^{inx}

x \to 0 + lim ((x + 1)^{in x})

1

Solution steps

x \to 0 + lim ((x + 1)^{in x})

Plug in the value

x = 0

= (0 + 1)^{in \cdot 0}

Simplify

= 1

6 x + 5 cos (x)

x \to \infty lim (x^{2} + x)

n = 0 \sum \infty \frac{5 ^{2 n}}{n !}

8 - x^{2}

\int 8 cos^{2} (5 x) d x

What is the limit as x approaches 0+of (x+1)^{inx} ?
The limit as x approaches 0+of (x+1)^{inx} is 1