What is (\partial)/(\partial x)(x^2-10x+y^2+8) ?

The answer to (\partial)/(\partial x)(x^2-10x+y^2+8) is 2x-10

Popular >

(\partial)/(\partial x)(x^2-10x+y^2+8)

\frac{\partial}{\partial x} (x^{2} - 10 x + y^{2} + 8)

2 x - 10

Solution steps

\frac{\partial}{\partial x} (x^{2} - 10 x + y^{2} + 8)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (10 x) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (8)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (10 x) = 10

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (8) = 0

= 2 x - 10 + 0 + 0

Simplify

= 2 x - 10

\frac{1}{( s ^{3} + 4 s )}

10 (t - 1)

(2 x - 5 y + 2) d x + (1 - 6 y - 5 x) d y = 0

\frac{\partial}{\partial x} ((2 x + 3 y)^{7})

\frac{d}{d x} (- 16 x^{2} + 64 x)

What is (\partial)/(\partial x)(x^2-10x+y^2+8) ?
The answer to (\partial)/(\partial x)(x^2-10x+y^2+8) is 2x-10