What is the derivative of y=34(3p+1)-2/5 ,p>0 ?

The derivative of y=34(3p+1)-2/5 ,p>0 is 0

What is the first derivative of y=34(3p+1)-2/5 ,p>0 ?

The first derivative of y=34(3p+1)-2/5 ,p>0 is 0

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derivative of

y = 34 (3 p + 1) - \frac{2}{5}, p > 0

0

Solution steps

\frac{d}{d x} (34 (3 p + 1) - \frac{2}{5})

Simplify

34 (3 p + 1) - \frac{2}{5} : 102 p + \frac{168}{5}

= \frac{d}{d x} (102 p + \frac{168}{5})

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

f (x) = 4 sin (x) + 3 cos (x), at x = 0

(x + 1)^{^{'}}

\int \frac{2 x - 4 + 8 x}{x} d x

x \to 1 lim (\frac{x ^{2} - 3 x}{x})

(2 x y + y^{4}) d x + (3 x^{2} + 6 x y^{3}) d y = 0

What is the derivative of y=34(3p+1)-2/5 ,p>0 ?
The derivative of y=34(3p+1)-2/5 ,p>0 is 0
What is the first derivative of y=34(3p+1)-2/5 ,p>0 ?
The first derivative of y=34(3p+1)-2/5 ,p>0 is 0