What is the limit as x approaches 0 of 4/(1+2^{1/x)} ?

The limit as x approaches 0 of 4/(1+2^{1/x)} is diverges

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limit as x approaches 0 of 4/(1+2^{1/x)}

x \to 0 lim (\frac{4}{1 + 2 ^{\frac{1}{x}}})

diverges

Solution steps

x \to 0 lim (\frac{4}{1 + 2 ^{\frac{1}{x}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{4}{1 + 2 ^{\frac{1}{x}}}) = 0

x \to 0 - lim (\frac{4}{1 + 2 ^{\frac{1}{x}}}) = 4

= diverges

\frac{d}{d x} (4 cos (4 x))

f^{^{'}} (x) = 3 x - 4, f (- 1) = \frac{13}{2}

ln (196 sin^{2} (x))

\int \frac{1}{5 - 7 x} d x

y^{^{''''}} + 4 y^{^{''}} + 4 y = 0

What is the limit as x approaches 0 of 4/(1+2^{1/x)} ?
The limit as x approaches 0 of 4/(1+2^{1/x)} is diverges