What is the derivative of 1-cos(x-1) ?

The derivative of 1-cos(x-1) is sin(x-1)

What is the first derivative of 1-cos(x-1) ?

The first derivative of 1-cos(x-1) is sin(x-1)

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\frac{d}{d x} (1 - cos (x - 1))

sin (x - 1)

Solution steps

\frac{d}{d x} (1 - cos (x - 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (cos (x - 1))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cos (x - 1)) = - sin (x - 1)

= 0 - (- sin (x - 1))

Simplify

= sin (x - 1)

\int \frac{e ^{5 x}}{5 x} d x

f (x) = 12 x - 2 x, at x = 9

\int \frac{3}{9 + x ^{2}} d x

e^{s i n (2 x)}

\int - 2 cos (x) + 3 x^{2} - 5 x + 4 d x

What is the derivative of 1-cos(x-1) ?
The derivative of 1-cos(x-1) is sin(x-1)
What is the first derivative of 1-cos(x-1) ?
The first derivative of 1-cos(x-1) is sin(x-1)