What is the derivative of 3x^4-8x^3+6x^2 ?

The derivative of 3x^4-8x^3+6x^2 is 12x^3-24x^2+12x

What is the first derivative of 3x^4-8x^3+6x^2 ?

The first derivative of 3x^4-8x^3+6x^2 is 12x^3-24x^2+12x

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\frac{d}{d x} (3 x^{4} - 8 x^{3} + 6 x^{2})

12 x^{3} - 24 x^{2} + 12 x

Solution steps

\frac{d}{d x} (3 x^{4} - 8 x^{3} + 6 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (8 x^{3}) + \frac{d}{d x} (6 x^{2})

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

= 12 x^{3} - 24 x^{2} + 12 x

y = x^{4} + 5 e^{x}

3 e^{3 e^{x} + x}

\int (e - x - e^{3}) (e x + e - 5) d x

\int_{9}^{x} 1 + 9 t d t

\int sec^{4} (3 x) tan^{2} (3 x) d x

What is the derivative of 3x^4-8x^3+6x^2 ?
The derivative of 3x^4-8x^3+6x^2 is 12x^3-24x^2+12x
What is the first derivative of 3x^4-8x^3+6x^2 ?
The first derivative of 3x^4-8x^3+6x^2 is 12x^3-24x^2+12x