What is laplacetransform e^{(t-2)} ?

The answer to laplacetransform e^{(t-2)} is 1/(e^2(s-1))

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laplacetransform e^{(t-2)}

laplace transform

e^{(t - 2)}

\frac{1}{e ^{2} ( s - 1 )}

Solution steps

L {e^{(t - 2)}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{- 2} L {e^{t}}

L {e^{t}} : \frac{1}{s - 1}

= e^{- 2} \frac{1}{s - 1}

Refine

e^{- 2} \frac{1}{s - 1} : \frac{1}{e ^{2} ( s - 1 )}

= \frac{1}{e ^{2} ( s - 1 )}

\int (3) d x

\frac{d}{d x} (\frac{1}{x ^{2} + x})

\int \frac{x}{sin ^{2} ( 2 x ^{2} )} d x

\int (sin (x) - 7 cos (x)) d x

\int 2 ∣ x ∣ d x

What is laplacetransform e^{(t-2)} ?
The answer to laplacetransform e^{(t-2)} is 1/(e^2(s-1))