What is the tangent of f(x)=3x-2x^2,(-2,-14) ?

The tangent of f(x)=3x-2x^2,(-2,-14) is y=11x+8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=3x-2x^2,(-2,-14)

tangent of

f (x) = 3 x - 2 x^{2}, (- 2, - 14)

y = 11 x + 8

Solution steps

Find the slope of

f (x) = 3 x - 2 x^{2} : \frac{df ( x )}{d x} = 3 - 4 x

Compute the slope of

f (x) = 3 x - 2 x^{2}

(- 2, - 14) : m = 11

Find the line with slope m=

11

and passing through

(- 2, - 14) : y = 11 x + 8

y = 11 x + 8

\frac{\partial}{\partial x} (- 6 x y - x^{6} - y^{6})

\int \frac{1}{6 x + 5} d x

\int 3 x + 3 d x

(y^{4} - x^{2}) (\frac{d y}{d x}) = - x y

\frac{d y}{d t} = 0.5 - t + 2 y

What is the tangent of f(x)=3x-2x^2,(-2,-14) ?
The tangent of f(x)=3x-2x^2,(-2,-14) is y=11x+8