What is the tangent of f(x)=xsqrt(x),(1,1) ?

The tangent of f(x)=xsqrt(x),(1,1) is y= 3/2 x-1/2

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tangent of f(x)=xsqrt(x),(1,1)

tangent of

f (x) = x x, (1, 1)

y = \frac{3}{2} x - \frac{1}{2}

Solution steps

Find the slope of

f (x) = x x : \frac{df ( x )}{d x} = \frac{3 x}{2}

Compute the slope of

f (x) = x x

(1, 1) : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(1, 1) : y = \frac{3}{2} x - \frac{1}{2}

y = \frac{3}{2} x - \frac{1}{2}

\int e^{4 x} sin (5 x) d x

x \to 0 lim (\frac{4}{x} - \frac{4}{x ^{2} + x})

\frac{d y}{d x} = \frac{( 2 x y )}{x ^{2} - y ^{2}}

\frac{d}{d a} (ab c d + 7 ab - 2 b c + 5 c d - 5)

\frac{d y}{d x} + 1 = 2 y, y (1) = 1

What is the tangent of f(x)=xsqrt(x),(1,1) ?
The tangent of f(x)=xsqrt(x),(1,1) is y= 3/2 x-1/2