What is the limit as x approaches 0 of 4/x-4/(x^2+x) ?

The limit as x approaches 0 of 4/x-4/(x^2+x) is 4

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limit as x approaches 0 of 4/x-4/(x^2+x)

x \to 0 lim (\frac{4}{x} - \frac{4}{x ^{2} + x})

4

Solution steps

x \to 0 lim (\frac{4}{x} - \frac{4}{x ^{2} + x})

Simplify

\frac{4}{x} - \frac{4}{x ^{2} + x} : \frac{4}{x + 1}

= x \to 0 lim (\frac{4}{x + 1})

Plug in the value

x = 0

= \frac{4}{0 + 1}

Simplify

= 4

\frac{d y}{d x} = \frac{( 2 x y )}{x ^{2} - y ^{2}}

\frac{d}{d a} (ab c d + 7 ab - 2 b c + 5 c d - 5)

\frac{d y}{d x} + 1 = 2 y, y (1) = 1

\int \frac{2 u - 1}{4 u ^{2} - 1} d u

\int \frac{4 y}{1} d y

What is the limit as x approaches 0 of 4/x-4/(x^2+x) ?
The limit as x approaches 0 of 4/x-4/(x^2+x) is 4