What is the integral from 0 to 6 of e^{-x^2} ?

The integral from 0 to 6 of e^{-x^2} is (sqrt(pi))/2

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integral from 0 to 6 of e^{-x^2}

\int_{0}^{6} e^{- x^{2}} d x

\frac{π}{2}

Decimal Notation

0.88622 \dots

Solution steps

\int_{0}^{6} e^{- x^{2}} d x

Use the nonelementary integral:

\int e^{- x^{2}} d x = \frac{π}{2} erf (x)

= [\frac{π}{2} erf (x)]_{0}^{6}

Compute the boundaries:

\frac{π}{2}

= \frac{π}{2}

\int_{0}^{\infty} x^{5} e^{- x} d x

\frac{\partial}{\partial x} (x^{10} + x y^{11} + 9)

\frac{d}{d x} (\frac{2 x}{1 + 4 x ^{2} + 9 x ^{4}})

\frac{d}{d x} (cos^{2} (x^{4}))

\int_{0}^{2} \frac{x}{8} d x

What is the integral from 0 to 6 of e^{-x^2} ?
The integral from 0 to 6 of e^{-x^2} is (sqrt(pi))/2