What is the solution for (dy)/(dx)-(2xy)/(x^2+1)=1 ?

The solution for (dy)/(dx)-(2xy)/(x^2+1)=1 is y=arctan(x)(x^2+1)+c_{1}(x^2+1)

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(dy)/(dx)-(2xy)/(x^2+1)=1

\frac{d y}{d x} - \frac{2 x y}{x ^{2} + 1} = 1

y = arctan (x) (x^{2} + 1) + c_{1} (x^{2} + 1)

Solution steps

\frac{d y}{d x} - \frac{2 x y}{x ^{2} + 1} = 1

Solve linear ODE:

y = arctan (x) (x^{2} + 1) + c_{1} (x^{2} + 1)

y = arctan (x) (x^{2} + 1) + c_{1} (x^{2} + 1)

\frac{d ^{2} y}{d x ^{2}} - 49 y = e^{7 x}

\int \frac{x}{8 - 2 x ^{2} - x ^{4}} d x

\int sin (7 x) d x

What is the solution for (dy)/(dx)-(2xy)/(x^2+1)=1 ?
The solution for (dy)/(dx)-(2xy)/(x^2+1)=1 is y=arctan(x)(x^2+1)+c_{1}(x^2+1)