What is the integral of sin^3(x)cos^{14}(x) ?

The integral of sin^3(x)cos^{14}(x) is -(cos^{15}(x))/(15)+(cos^{17}(x))/(17)+C

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integral of sin^3(x)cos^{14}(x)

\int sin^{3} (x) cos^{14} (x) d x

- \frac{cos ^{15} ( x )}{15} + \frac{cos ^{17} ( x )}{17} + C

Solution steps

\int sin^{3} (x) cos^{14} (x) d x

Rewrite using trig identities

= \int (1 - cos^{2} (x)) sin (x) cos^{14} (x) d x

Apply u-substitution

: \int - u^{14} (1 - u^{2}) d u

= \int - u^{14} (1 - u^{2}) d u

Expand

- u^{14} (1 - u^{2}) : - u^{14} + u^{16}

= \int - u^{14} + u^{16} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int u^{14} d u + \int u^{16} d u

\int u^{14} d u = \frac{u ^{15}}{15}

\int u^{16} d u = \frac{u ^{17}}{17}

= - \frac{u ^{15}}{15} + \frac{u ^{17}}{17}

Substitute back

u = cos (x)

= - \frac{cos ^{15} ( x )}{15} + \frac{cos ^{17} ( x )}{17}

Add a constant to the solution

= - \frac{cos ^{15} ( x )}{15} + \frac{cos ^{17} ( x )}{17} + C

a \to - 1 lim (a)

x \to 0 + lim (x \cdot ln (x^{4}))

\int \frac{1}{x ^{2} ( x ^{2} - 9 )} d x

\int (\frac{1}{x ( 2 x ^{2} - x + 1 ) ( x + 1 )}) d x

(1, 2), (- 1, - 2)

What is the integral of sin^3(x)cos^{14}(x) ?
The integral of sin^3(x)cos^{14}(x) is -(cos^{15}(x))/(15)+(cos^{17}(x))/(17)+C