What is the derivative of y=sin(tan(8x)) ?

The derivative of y=sin(tan(8x)) is cos(tan(8x))sec^2(8x)*8

What is the first derivative of y=sin(tan(8x)) ?

The first derivative of y=sin(tan(8x)) is cos(tan(8x))sec^2(8x)*8

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derivative of

y = sin (tan (8 x))

cos (tan (8 x)) sec^{2} (8 x) \cdot 8

Solution steps

\frac{d}{d x} (sin (tan (8 x)))

Apply the chain rule:

cos (tan (8 x)) \frac{d}{d x} (tan (8 x))

= cos (tan (8 x)) \frac{d}{d x} (tan (8 x))

\frac{d}{d x} (tan (8 x)) = sec^{2} (8 x) \cdot 8

= cos (tan (8 x)) sec^{2} (8 x) \cdot 8

x \to 9 lim (\frac{1}{( x - 9 ) ^{2}})

\frac{\partial}{\partial x} (1 - x^{2} + y^{2})

x \to 0 + lim ((\frac{2}{x})^{x})

y = e^{x}, y = e^{- 3 x}, x = ln (4)

7 - 2 x

What is the derivative of y=sin(tan(8x)) ?
The derivative of y=sin(tan(8x)) is cos(tan(8x))sec^2(8x)*8
What is the first derivative of y=sin(tan(8x)) ?
The first derivative of y=sin(tan(8x)) is cos(tan(8x))sec^2(8x)*8