What is the solution for y^{''}+5y^'+6=0 ?

The solution for y^{''}+5y^'+6=0 is y=c_{1}+c_{2}e^{-5t}-(6t)/5

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y^{''}+5y^'+6=0

y^{^{''}} + 5 y^{^{'}} + 6 = 0

y = c_{1} + c_{2} e^{- 5 t} - \frac{6 t}{5}

Solution steps

y^{''} (t) + 5 y^{'} (t) + 6 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 5 t} - \frac{6 t}{5}

y = c_{1} + c_{2} e^{- 5 t} - \frac{6 t}{5}

y = sin (sin (x)), (4 π, 0)

\frac{d}{d x} (3 x^{2} - 15)

n = 1 \sum \infty \frac{n}{n + 6}

x \to 0 lim ((1 - 6 x)^{\frac{2}{x}})

\int \frac{1}{x ^{11}} d x

What is the solution for y^{''}+5y^'+6=0 ?
The solution for y^{''}+5y^'+6=0 is y=c_{1}+c_{2}e^{-5t}-(6t)/5