What is the integral of x^2ln(8x) ?

The integral of x^2ln(8x) is 1/3 x^3ln(8x)-(x^3)/9+C

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integral of x^2ln(8x)

\int x^{2} ln (8 x) d x

\frac{1}{3} x^{3} ln (8 x) - \frac{x ^{3}}{9} + C

Solution steps

\int x^{2} ln (8 x) d x

Apply Integration By Parts

: \frac{1}{3} x^{3} ln (8 x) - \int \frac{x ^{2}}{3} d x

= \frac{1}{3} x^{3} ln (8 x) - \int \frac{x ^{2}}{3} d x

\int \frac{x ^{2}}{3} d x = \frac{x ^{3}}{9}

= \frac{1}{3} x^{3} ln (8 x) - \frac{x ^{3}}{9}

Add a constant to the solution

= \frac{1}{3} x^{3} ln (8 x) - \frac{x ^{3}}{9} + C

\frac{d}{d x} (6 - 2 x)

\int sin^{3} (θ) d θ

\frac{\partial}{\partial u} (\frac{u + v}{3})

49 y^{^{''}} + 126 y^{^{'}} + 81 y = 0

What is the integral of x^2ln(8x) ?
The integral of x^2ln(8x) is 1/3 x^3ln(8x)-(x^3)/9+C