What is the derivative of x6^x ?

The derivative of x6^x is 6^x+ln(6)*6^xx

What is the first derivative of x6^x ?

The first derivative of x6^x is 6^x+ln(6)*6^xx

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derivative of

x 6^{x}

6^{x} + ln (6) \cdot 6^{x} x

Solution steps

\frac{d}{d x} (x \cdot 6^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 6^{x}

= \frac{d x}{d x} 6^{x} + \frac{d}{d x} (6^{x}) x

\frac{d x}{d x} = 1

\frac{d}{d x} (6^{x}) = 6^{x} ln (6)

= 1 \cdot 6^{x} + 6^{x} ln (6) x

Simplify

= 6^{x} + ln (6) \cdot 6^{x} x

\frac{\partial}{\partial x} (\frac{1}{x + 3})

x \to 0 lim (x^{2} - 1)

\frac{\partial}{\partial x} (21 x y e^{- x^{2} - y^{2}})

\int e^{5 x} e^{5 x} + 4 d x

f (x) = (x + \frac{1}{x}) (2 - x^{2})

What is the derivative of x6^x ?
The derivative of x6^x is 6^x+ln(6)*6^xx
What is the first derivative of x6^x ?
The first derivative of x6^x is 6^x+ln(6)*6^xx