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Popular >

xy^'-y=-x^2+x-1

Solution

x y^{^{'}} - y = - x^{2} + x - 1

Solution

y = - x^{2} + x ln (x) + 1 + c_{1} x

Solution steps

x y^{'} (x) - y = - x^{2} + x - 1

Solve linear ODE:

y = - x^{2} + x ln (x) + 1 + c_{1} x

y = - x^{2} + x ln (x) + 1 + c_{1} x

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Frequently Asked Questions (FAQ)

What is the solution for xy^'-y=-x^2+x-1 ?
The solution for xy^'-y=-x^2+x-1 is y=-x^2+xln(x)+1+c_{1}x